TEMA: EXPONENTES Y RADICALES
1.- Si: a + b = 10; ab = 25
Determine: a² + b²
Recordemos esto:
a² + b² = (a + b)² - 2ab
Así que operamos:
a² + b² = (10)² - 2(25)
a² + b² = 100 - 50
a² + b² = 50
RPTA: a² + b² = 50
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2.- Efectúa:
[tex]\sqrt[8]{35(6^2+1)(6^4+1)+1}}}}[/tex]
Solo hay que operar
[tex]\sqrt[8]{35(36+1)(1296+1)+1}}}}\\\\\sqrt[8]{35(37)(1297)+1}}}}\\\\\sqrt[8]{1~679~615+1}}}}\\\\\sqrt[8]{1~679~616}}}}\\\\\Large \boxed{\mathbf{=6}}[/tex]
RPTA: [tex]\sqrt[8]{35(6^2+1)(6^4+1)+1}}}}[/tex] = 6
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3.- Si: aᵃ = 3, calcular [tex]\mathbf{a^{a^{a+1} }}[/tex]
Entonces podemos decir:
[tex]\mathbf{{3^{a+1} }=3^3= 27}[/tex]
RPTA: 27
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4.- Efectúe:
[tex]\mathbf{3^{2}+(3^{2})^{3}-27^{2}+\frac{1}{5} ^{-1} }\\[/tex]
Operamos.
[tex]\mathbf{3^{2}+(3^{2})^{3}-27^{2}+\frac{1}{5} ^{-1}}\\\\\mathbf{9+729-729+\frac{5}{1} ^{1}}\\\\\mathbf{9+\frac{5}{1} ^{1}}\\\\\mathbf{9+5}\\\\\Large \boxed{\mathbf{=14}}[/tex]
RPTA: 14
ᗩTTE: ᗰIᖇOKᑌ[̲̅2][̲̅4]
