Respuesta:
[tex] \frac{125}{84} [/tex]
Explicación paso a paso:
[tex] {4.5}^{ - } = 4 + {0.5}^{ - } = 4 + \frac{5}{9} = \frac{41}{9}[/tex]
[tex] {2.8}^{ - } = 2 + {0.8}^{ - } = 2 + \frac{8}{9} = \frac{26}{9}[/tex]
[tex] {1.26}^{ - } = 1 + {0.26}^{ - } = 1 + \frac{26}{99} = \frac{125}{99} [/tex]
[tex] {2.42}^{ - } = 2 + {0.42}^{ - } = 2 + \frac{42}{99} = \frac{240}{99} [/tex]
[tex] {8.6}^{ - } = 8 + {0.6}^{ - } = 8 + \frac{6}{9} = \frac{78}{9} [/tex]
[tex] {5.3}^{ - } = 5 + {0.3}^{ - } = 5 + \frac{3}{9} = \frac{48}{9} [/tex]
Remplazando en el numerador:
[tex] ( \frac{41}{9} - \frac{26}{9})(3)( \frac{125}{99}) = ( \frac{15}{9})(3)( \frac{125}{99}) =(5)( \frac{125}{99}) = ( \frac{5 \times 125}{99})[/tex]
Remplazando en el denominador:
[tex]( \frac{21}{10})( \frac{240}{99})( \frac{25}{100})( \frac{78}{9} - \frac{48}{9}) =( \frac{21}{10})( \frac{60}{99})( \frac{30}{9}) = ( \frac{21 \times 20}{99})[/tex]
Remplazando valores en R:
[tex] \frac{ \frac{5 \times 125}{99} }{ \frac{21 \times 20}{99} } = \frac{5 \times 125}{21 \times 20} = \frac{125}{84} [/tex]
