La ecuación escalar que utilizaremos para determinar la distancia en un movimiento rectilíneo uniforme(MRU) es:
[tex]\boxed{\ \boldsymbol{\mathsf{\vphantom{\Big|}d=vt}}\ }\hspace{30pt} \mathsf{Donde} \hspace{25pt} \begin{array}{l}\mathsf{\blue{\blacktriangleright}\:\:\:v:rapidez}\\\\\mathsf{\blue{\blacktriangleright}\:\:\:d:distancia}\\\\\mathsf{\blue{\blacktriangleright}\:\:\:t:tiempo}\end{array}[/tex]
Extraemos los datos del problema:
[tex]\begin{array}{cccccccccccccccccccc}\mathsf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ t=3\ s}&&&&&&&&&&&&\mathsf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ v=15\ m/s}\end{array}[/tex]
Reemplazamos estos valores en la ecuación escalar anterior.
[tex]\begin{array}{c}\mathsf{d = v\times\: t}\\\\\\\mathsf{d = (15\:\dfrac{m}{s})\times\:(3\:s)}\\\\\\\mathsf{\:d = (15\:\dfrac{m}{\not \!s})\times\:(3\!\not \!s)}\\\\\\\mathsf{\boxed{\boxed{\boldsymbol{\mathsf{d = 45\:m}}}}}\end{array}[/tex]
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