Respuesta:
Explicación paso a paso:
[tex]\frac{2}{3} x-\frac{1}{2} =x+\frac{3}{4} \\\\\frac{2}{3} x-x= \frac{3}{4}+\frac{1}{2}\\\\\frac{2}{3}x-x=\frac{5}{4}\\[/tex]
[tex]\frac{2}{3}x-x*3=\frac{5}{4}*3\\\\2x-3x=\frac{5}{4}*3\\\\-x=\frac{15}{4}\\\\(-1)(-x=\frac{15}{4})\\\\x=\left-\frac{15}{4}\right[/tex]
Verificación remplazamos (x= -15/4)
[tex]\frac{2}{3} x-\frac{1}{2} =x+\frac{3}{4} \\\\\frac{2}{3}\:\left(-\frac{15}{4}\right)-\frac{1}{2}\:=\left(-\frac{15}{4}\right)+\frac{3}{4}\:\\\\-\frac{2}{3}\cdot \frac{15}{4}-\frac{1}{2}=\frac{-15+3}{4}\\\\\frac{30}{12}-\frac{1}{2}=\frac{-12}{4} \\\\\frac{5}{2} -\frac{1}{2}=\frac{-12}{4} \\\\\frac{-5-1}{2}=\frac{-12}{4}\\\\\frac{-6}{2}=\frac{-12}{4}\\\\-3=-3[/tex]
La igualdad es correcta asi que el valor de x es correcto
